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3v^2-12v-135=0
a = 3; b = -12; c = -135;
Δ = b2-4ac
Δ = -122-4·3·(-135)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-42}{2*3}=\frac{-30}{6} =-5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+42}{2*3}=\frac{54}{6} =9 $
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